[ale] Bash: How to determine if called from cron?

[Christopher Fowler]

That won't work either.  I think tty does a isatty check.  My script
that looks like this:

#!/bin/sh

FD1=`ls -l /proc/$$/fd/1 | cut -d '>' -f2`
echo $FD1 >> /tmp/test.sh.out

Gave me this:
[cfowler at cfowler tmp]$ tail /tmp/test.sh.out 
pipe:[266205]
pipe:[267448]
pipe:[268442]
pipe:[269312]


On Mon, 2005-06-27 at 09:24, David A. De Graaf wrote:
> On Mon, Jun 27, 2005 at 12:17:00AM -0400, Christopher Bergeron wrote:
> > Does anyone know of an easy way for my script to determine if it's being 
> > run from cron or from a user shell? 
> 
> Read about the 'tty' command.
> Try this example script, both manually and via cron:
> 
>   ANS=`tty`
>   echo ANS: $ANS